Networking Foundation
Fundamentals · Implementations · Operations · Security · Troubleshooting · 70 questions
⚠️ Exam Rules
| Questions in this Techclick bank | 70 |
|---|---|
| Timer | 90 min |
| Techclick practice target | 70% |
| Official exam code | N10-009 |
A technician captures traffic and sees a frame being forwarded based on its destination MAC address before any IP header is read. At which OSI layer is this forwarding decision being made?
Correct: A. Switches forward frames using destination MAC addresses, which live in the Layer 2 Data Link header, so this is a Layer 2 decision. It is not Layer 3 because no IP address is consulted, not Layer 4 because no port or segment is involved, and not Layer 1 because the Physical layer only moves bits and has no addressing.
An engineer maps protocols to OSI layers while documenting a stack. Which of the following protocol-to-layer pairings are correct? (Choose TWO)
Correct: A and B. IP provides logical addressing at Layer 3 and TCP provides reliable segments at Layer 4, so both pairings are correct. Ethernet is a Data Link Layer 2 protocol not Session, HTTP is an Application Layer 7 protocol not Physical, and ARP works between Layers 2 and 3 rather than at the Presentation layer, so those three are wrong.
While documenting an addressing scheme, an administrator must note the bit length of a standard IPv4 address versus an IPv6 address. What is the correct pair of bit lengths?
Correct: A. IPv4 uses a 32-bit address space and IPv6 expands this to 128 bits to vastly enlarge the pool. The other options are incorrect because IPv4 is never 64 or 48 bits, and IPv6 is not 64 bits; 48 bits is actually the length of a MAC address, which is unrelated to logical IP addressing.
A company is choosing internal address blocks that will not be routed on the public Internet. Which of the following are RFC 1918 private IPv4 ranges? (Choose THREE)
Correct: A and B and C. RFC 1918 reserves 10.0.0.0/8, 172.16.0.0/12, and 192.168.0.0/16 for private internal use. The range 169.254.0.0/16 is incorrect because it is APIPA link-local addressing assigned when DHCP fails, and 8.8.8.0/24 is incorrect because it is public space, not private.
A network is divided using a /26 subnet mask. How many usable host addresses are available in each /26 subnet?
Correct: A. A /26 leaves 6 host bits, giving 2^6 = 64 total addresses, and subtracting the network and broadcast addresses leaves 62 usable hosts. The answer is not 64 because those two reserved addresses cannot be assigned, not 30 which is a /27, and not 126 which is a /25.
Last updated:
Yes. You can start, finish and score it for free, and download the Techclick practice certificate.
This bank has 70 original scenario-based questions with a 90-minute timer and a 70% Techclick practice target.
The official exam code is N10-009 (CompTIA).
No. They are original practice questions written by Techclick. This is not the vendor's official exam and not leaked dumps.
Score 70% or higher to get a Techclick practice certificate and LinkedIn badge. It is not an official CompTIA certification.
Related practice tests: SY0-701, 200-301, 220-1101/220-1102, XK0-005, SK0-005, hardware networking (linked below).

You earned it — let the world know!
